courtney-brown_60b2621992f12
courtney-brown_60b2621992f12
About
- Username
- courtney-brown_60b2621992f12
- Joined
- Visits
- 0
- Last Active
- Roles
- Member
Comments
-
Ok, veja como resolver, I= ʃ (cos³x / sen⁴x) dx = ʃ [(cos³x / sen³x)∙(1/sen x)] dx = ʃ cotg³x∙cossecx dx = ʃ cotg²x∙cotgx∙cossecx dx = ʃ (cossec²x - 1)∙cotgx∙cossecx dx ~~ > pois cotg²x = cossec²x -1 = ʃ cossec²x∙cotgx∙cossecx d…