Comments

• cateto/hipotenusa=0,6 10cm/hipotenusa=0,6 hipotenusa=10/0,6 hipotenusa=100/6 (100/6)²=10²+c² c²=(100/6)²-10² c²=(10.000/36)-100 c²=(10.000-3.600)/36 c²=6.400/36 c=²V(6.400/36) c=80/6 c=40/3 h=100/6 h=50/3

  in Num triângulo retângulo,um cateto mede 10cm e o cosseno do ângulo agudo adjacente a ele vale 0,6? Comment by connor-morgan_60a0c1a41f82d May 2021