Comments

• I agree with QM. The problem with self defense classes are: 1. They are usually for a set amount of time, not ongoing. Therefore, you learn something but don't repeat it for an indefinite amount of time so you forget it. By not getting a chan…

  in How to choose a self defense class? Comment by cheetah June 2021
• 2+cosx d/dx = -sinx let 2+cosx =u du = -sinx dx then, remember ∫du/u = ln u yet, you need to multiply 1/(2+cosx) by -1/-1 to satisfy the fromula above ∫(-1/-1)[1/(2+cosx)](sinx) dx then extract the constant 1/-1 1/-1 ∫1/(2+cosx…

  in How do ∫1/[(2+cosx)*sinx] dx? Comment by cheetah June 2021
• 2+cosx d/dx = -sinx let 2+cosx =u du = -sinx dx then, remember ∫du/u = ln u yet, you need to multiply 1/(2+cosx) by -1/-1 to satisfy the fromula above ∫(-1/-1)[1/(2+cosx)](sinx) dx then extract the constant 1/-1 1/-1 ∫1/(2+cosx…

  in How do ∫1/[(2+cosx)*sinx] dx? Comment by cheetah June 2021
• Comfortably Numb, but Time is a very close second for me.

  in comfortably numb vs time vs dogs? Comment by cheetah May 2021
• ¿Como aprendo a ser ingeniero? - Estudia una carrera. Actuación es una profesión. Hay lugares donde dan clases, cursos, diplomados y carrera completa. Y a propósito la mima y actuación no tienen nada que ver uno con el otro.

  in ¿Como aprendo a actuar? Comment by cheetah May 2021
• ¿Como aprendo a ser ingeniero? - Estudia una carrera. Actuación es una profesión. Hay lugares donde dan clases, cursos, diplomados y carrera completa. Y a propósito la mima y actuación no tienen nada que ver uno con el otro.

  in ¿Como aprendo a actuar? Comment by cheetah May 2021
• ¿Como aprendo a ser ingeniero? - Estudia una carrera. Actuación es una profesión. Hay lugares donde dan clases, cursos, diplomados y carrera completa. Y a propósito la mima y actuación no tienen nada que ver uno con el otro.

  in ¿Como aprendo a actuar? Comment by cheetah May 2021
• Comfortably Numb, but Time is a very close second for me.

  in comfortably numb vs time vs dogs? Comment by cheetah May 2021
• 2+cosx d/dx = -sinx let 2+cosx =u du = -sinx dx then, remember ∫du/u = ln u yet, you need to multiply 1/(2+cosx) by -1/-1 to satisfy the fromula above ∫(-1/-1)[1/(2+cosx)](sinx) dx then extract the constant 1/-1 1/-1 ∫1/(2+cosx…

  in How do ∫1/[(2+cosx)*sinx] dx? Comment by cheetah May 2021
• I agree with QM. The problem with self defense classes are: 1. They are usually for a set amount of time, not ongoing. Therefore, you learn something but don't repeat it for an indefinite amount of time so you forget it. By not getting a chan…

  in How to choose a self defense class? Comment by cheetah May 2021