cattbarf
cattbarf
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Don't guess. Just read the problem. Let x and y be the two numbers. So x+y=8 And, we want to minimize x^3+y^2 Typically, d(x^3+y^2)/d(something) = 0 So if we let y=8-x, then, x^3 +(8-x)^2 = SUM Then d(SUM)/dx = 3x^2 + 2x -16 So at the min…
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Don't guess. Just read the problem. Let x and y be the two numbers. So x+y=8 And, we want to minimize x^3+y^2 Typically, d(x^3+y^2)/d(something) = 0 So if we let y=8-x, then, x^3 +(8-x)^2 = SUM Then d(SUM)/dx = 3x^2 + 2x -16 So at the min…
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Find angle B from law of sines (a/Sin A = b/Sin B) Likewise, find C. You can find c from law of Cosines (c^2=a^2+b^2-2ab Cos C)
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If he is honest, 14.4 pounds (12 x 1.2 lb/pack)
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If he is honest, 14.4 pounds (12 x 1.2 lb/pack)
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If he is honest, 14.4 pounds (12 x 1.2 lb/pack)
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Don't guess. Just read the problem. Let x and y be the two numbers. So x+y=8 And, we want to minimize x^3+y^2 Typically, d(x^3+y^2)/d(something) = 0 So if we let y=8-x, then, x^3 +(8-x)^2 = SUM Then d(SUM)/dx = 3x^2 + 2x -16 So at the min…