carole-murray_60b98c34f2320
carole-murray_60b98c34f2320
About
- Username
- carole-murray_60b98c34f2320
- Joined
- Visits
- 0
- Last Active
- Roles
- Member
Comments
-
M = C.(1+i)^n log1,08 = log(108/100) log1,08 = log108-log100 log1,08 = log(2^2*3^3) - 2 log1,08 = 2log2 + 3log3 - 2 log1,08 = 2*0,3 + 3*0,48 - 2 log1,08 = 0,04 10000 = 5000.(1,08)^n 1,08^n = 2 n = log2/log1,08 n = 0,3/0,04 n = 7,5 anos