bskelkar
bskelkar
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What is #? and what is 8?
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x² -5x +6 <0 2<x,3 x² -5x +6 >0 x< 2 or 3<x (x-1)(x-3)(x-5)<0 x<1 or 3<x<5 (x-1)(x-3)(x-5)>0 1<x<3 or 5<x It has to be done by drawing a graph
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(x-5)(2x+3) Instead of coming for evry problem to Y!A, why not learn how to factorise a quadratic first?
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(x-5)(2x+3) Instead of coming for evry problem to Y!A, why not learn how to factorise a quadratic first?
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obviously inverse of f is (x - 4)/2. which not g(x). so fog and gof can't be identity functions. its a G.P with c.r. (1-i) so 11th terms is (1+i)[(1-i)^10] Note that (1+i)(1-i) =2.
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obviously inverse of f is (x - 4)/2. which not g(x). so fog and gof can't be identity functions. its a G.P with c.r. (1-i) so 11th terms is (1+i)[(1-i)^10] Note that (1+i)(1-i) =2.
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1. Mother, Mummy, Mom or whatever. It is his choice. 2. Sally. 3. Take only one sock from RED and only one sock from GREEN. (The condition does not say only one sock from only one box) 4. Its 12000+1200+12 = 13212.
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Write the equations of the line thr these points. They are (x-2)/2 + (y-3)/-5 = (z-1)/4 = t say so x= (2t+2) y = (-5t+3) and z = (4t + 1) for any point on the line. Now find t by substituting thesex, y and z in the equation of the plane, find t an…
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Write the equations of the line thr these points. They are (x-2)/2 + (y-3)/-5 = (z-1)/4 = t say so x= (2t+2) y = (-5t+3) and z = (4t + 1) for any point on the line. Now find t by substituting thesex, y and z in the equation of the plane, find t an…
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Plane mirrors don't! Concave and convex mirror do!
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Plane mirrors don't! Concave and convex mirror do!
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Write the equations of the line thr these points. They are (x-2)/2 + (y-3)/-5 = (z-1)/4 = t say so x= (2t+2) y = (-5t+3) and z = (4t + 1) for any point on the line. Now find t by substituting thesex, y and z in the equation of the plane, find t an…
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1. Mother, Mummy, Mom or whatever. It is his choice. 2. Sally. 3. Take only one sock from RED and only one sock from GREEN. (The condition does not say only one sock from only one box) 4. Its 12000+1200+12 = 13212.
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1. Mother, Mummy, Mom or whatever. It is his choice. 2. Sally. 3. Take only one sock from RED and only one sock from GREEN. (The condition does not say only one sock from only one box) 4. Its 12000+1200+12 = 13212.
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1. Mother, Mummy, Mom or whatever. It is his choice. 2. Sally. 3. Take only one sock from RED and only one sock from GREEN. (The condition does not say only one sock from only one box) 4. Its 12000+1200+12 = 13212.
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obviously inverse of f is (x - 4)/2. which not g(x). so fog and gof can't be identity functions. its a G.P with c.r. (1-i) so 11th terms is (1+i)[(1-i)^10] Note that (1+i)(1-i) =2.
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x² -5x +6 <0 2<x,3 x² -5x +6 >0 x< 2 or 3<x (x-1)(x-3)(x-5)<0 x<1 or 3<x<5 (x-1)(x-3)(x-5)>0 1<x<3 or 5<x It has to be done by drawing a graph