Comments

• Since x=3 is a solution, (x-3) is a factor. I would use synthetic division to figure out the rest: (x-3)(x^2+3x+9).

  in How do you factor X^3 - 27?? Comment by bruinfan May 2021
• Since x=3 is a solution, (x-3) is a factor. I would use synthetic division to figure out the rest: (x-3)(x^2+3x+9).

  in How do you factor X^3 - 27?? Comment by bruinfan May 2021
• This parabola can be modeled by the equation y=ax^2+12. We just have to find out what a equals. When x=4, the height is 10, so solve this: 10=16a+12 or -2=16a or a=-1/8. So the equation is y=(-1/8)x^2+12

  in Parabola Problem help? Comment by bruinfan May 2021
• This parabola can be modeled by the equation y=ax^2+12. We just have to find out what a equals. When x=4, the height is 10, so solve this: 10=16a+12 or -2=16a or a=-1/8. So the equation is y=(-1/8)x^2+12

  in Parabola Problem help? Comment by bruinfan May 2021
• Since x=3 is a solution, (x-3) is a factor. I would use synthetic division to figure out the rest: (x-3)(x^2+3x+9).

  in How do you factor X^3 - 27?? Comment by bruinfan May 2021