azlender
azlender
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5 x 8.5 = 42.5, so position all the pieces with the 8.5" side along the 43" width. You can have 5 rows across. An optimal length (instead of 48") would then be any exact multiple of 11". From a 43"x44" piece you w…
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The question and diagram are incomprehensible. Try again.
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The question and diagram are incomprehensible. Try again.
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The question and diagram are incomprehensible. Try again.
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The question and diagram are incomprehensible. Try again.
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5 x 8.5 = 42.5, so position all the pieces with the 8.5" side along the 43" width. You can have 5 rows across. An optimal length (instead of 48") would then be any exact multiple of 11". From a 43"x44" piece you w…
-
5 x 8.5 = 42.5, so position all the pieces with the 8.5" side along the 43" width. You can have 5 rows across. An optimal length (instead of 48") would then be any exact multiple of 11". From a 43"x44" piece you w…
-
The question and diagram are incomprehensible. Try again.
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The question and diagram are incomprehensible. Try again.
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Summary of what appears below the first line of asterisks: (a) For this one, I present an argument not dependent on the classic Taylor series method, but valid all the same. (b) For this one, I attack through the classic Taylor series method. …
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Summary of what appears below the first line of asterisks: (a) For this one, I present an argument not dependent on the classic Taylor series method, but valid all the same. (b) For this one, I attack through the classic Taylor series method. …
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Summary of what appears below the first line of asterisks: (a) For this one, I present an argument not dependent on the classic Taylor series method, but valid all the same. (b) For this one, I attack through the classic Taylor series method. …
-
The question and diagram are incomprehensible. Try again.
-
5 x 8.5 = 42.5, so position all the pieces with the 8.5" side along the 43" width. You can have 5 rows across. An optimal length (instead of 48") would then be any exact multiple of 11". From a 43"x44" piece you w…
-
5 x 8.5 = 42.5, so position all the pieces with the 8.5" side along the 43" width. You can have 5 rows across. An optimal length (instead of 48") would then be any exact multiple of 11". From a 43"x44" piece you w…