Comments

• Firstly, remember the newtonian Laws of Motion: If x=dist, v=velocity, a accel., v=dx/dt a=dv/dt Hence, v=d(9ln(1+t)-4t)/dt =[9/(1+t)]-4 a=dv/dt =-9/(1+t)^2 But v=a Hence, [9/(1+t)]-4=-9/(1+t)^2 Let 1/(t+t)=x. 9x-4=-9x^2 9x^2+9…

  in second derivative problem? Comment by ayush June 2021
• Firstly, remember the newtonian Laws of Motion: If x=dist, v=velocity, a accel., v=dx/dt a=dv/dt Hence, v=d(9ln(1+t)-4t)/dt =[9/(1+t)]-4 a=dv/dt =-9/(1+t)^2 But v=a Hence, [9/(1+t)]-4=-9/(1+t)^2 Let 1/(t+t)=x. 9x-4=-9x^2 9x^2+9…

  in second derivative problem? Comment by ayush May 2021
• Firstly, remember the newtonian Laws of Motion: If x=dist, v=velocity, a accel., v=dx/dt a=dv/dt Hence, v=d(9ln(1+t)-4t)/dt =[9/(1+t)]-4 a=dv/dt =-9/(1+t)^2 But v=a Hence, [9/(1+t)]-4=-9/(1+t)^2 Let 1/(t+t)=x. 9x-4=-9x^2 9x^2+9…

  in second derivative problem? Comment by ayush May 2021