awms-a
awms-a
About
- Username
- awms-a
- Joined
- Visits
- 0
- Last Active
- Roles
- Member
Comments
-
There are a couple ways to do this. My preference is actually to use geometry. The following works because the perpendicular bisector of CD is the collection of all points whose distance from C is the same as its distance from D. Therefore we j…
-
Well, for the first, if (0,0,0) were in there, then we'd have (x1, x2, 1) = (0, 0, 0) which is actually three equations: x1 = 0 x2 = 0 1 = 0 The first two equations are fine; however, the last, 1=0, is a contradiction, so (0,0,0) must not be…
-
Well, for the first, if (0,0,0) were in there, then we'd have (x1, x2, 1) = (0, 0, 0) which is actually three equations: x1 = 0 x2 = 0 1 = 0 The first two equations are fine; however, the last, 1=0, is a contradiction, so (0,0,0) must not be…
-
Well, for the first, if (0,0,0) were in there, then we'd have (x1, x2, 1) = (0, 0, 0) which is actually three equations: x1 = 0 x2 = 0 1 = 0 The first two equations are fine; however, the last, 1=0, is a contradiction, so (0,0,0) must not be…