asimov
asimov
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i take instead of ≤ , just = and we have 2 even 2x₁ + x₂ + 3x₃ = 10 x₁ + 3x₂ + 4x₃ = 15 find the common line multiple 1st equation with -3 and add to secod one -6x₁ - 3x₂ - 9x₃ = -30 x₁ + 3x₂ + 4x₃ = 15 ------------------------------- -…
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(pq) =(q) - (p) =( -10/5) as unit (-10/5) / root(125)
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T5 = { 1, -1 , 5 , -5} this are the best numbers to try after try them you can see that x= -1 is a correct answer and then you can dividing x³-6x-5 by (x+1) | 1 | 0 | -6 | -5 | | 0 | -1 | 1 | 5 | | 1 | -1 | -5 | 0 | solution x² -x …
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T5 = { 1, -1 , 5 , -5} this are the best numbers to try after try them you can see that x= -1 is a correct answer and then you can dividing x³-6x-5 by (x+1) | 1 | 0 | -6 | -5 | | 0 | -1 | 1 | 5 | | 1 | -1 | -5 | 0 | solution x² -x …
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T5 = { 1, -1 , 5 , -5} this are the best numbers to try after try them you can see that x= -1 is a correct answer and then you can dividing x³-6x-5 by (x+1) | 1 | 0 | -6 | -5 | | 0 | -1 | 1 | 5 | | 1 | -1 | -5 | 0 | solution x² -x …
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(pq) =(q) - (p) =( -10/5) as unit (-10/5) / root(125)
-
(pq) =(q) - (p) =( -10/5) as unit (-10/5) / root(125)
-
i take instead of ≤ , just = and we have 2 even 2x₁ + x₂ + 3x₃ = 10 x₁ + 3x₂ + 4x₃ = 15 find the common line multiple 1st equation with -3 and add to secod one -6x₁ - 3x₂ - 9x₃ = -30 x₁ + 3x₂ + 4x₃ = 15 ------------------------------- -…