Comments

• a million) 3000 = 2(2 + e^2x) 1500 = 2 + e^2x 1498 = e^2x Take organic log of the two aspects ln is organic log. ln(1498) = ln(e^2x) ln(1498) = 2x x = ln(1498)/2 2) 10^(x-6) = 7/5 x - 6 = (7/5)^(a million/10) x = (7/5)^(a million/10) + 6 3) log(15xy…

  in precalc-natural logs? Comment by arwood June 2021
• a million) 3000 = 2(2 + e^2x) 1500 = 2 + e^2x 1498 = e^2x Take organic log of the two aspects ln is organic log. ln(1498) = ln(e^2x) ln(1498) = 2x x = ln(1498)/2 2) 10^(x-6) = 7/5 x - 6 = (7/5)^(a million/10) x = (7/5)^(a million/10) + 6 3) log(15xy…

  in precalc-natural logs? Comment by arwood June 2021
• a million) 3000 = 2(2 + e^2x) 1500 = 2 + e^2x 1498 = e^2x Take organic log of the two aspects ln is organic log. ln(1498) = ln(e^2x) ln(1498) = 2x x = ln(1498)/2 2) 10^(x-6) = 7/5 x - 6 = (7/5)^(a million/10) x = (7/5)^(a million/10) + 6 3) log(15xy…

  in precalc-natural logs? Comment by arwood May 2021
• a million) 3000 = 2(2 + e^2x) 1500 = 2 + e^2x 1498 = e^2x Take organic log of the two aspects ln is organic log. ln(1498) = ln(e^2x) ln(1498) = 2x x = ln(1498)/2 2) 10^(x-6) = 7/5 x - 6 = (7/5)^(a million/10) x = (7/5)^(a million/10) + 6 3) log(15xy…

  in precalc-natural logs? Comment by arwood May 2021