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• P (2,5) Q (1,4) a=y2-y1/x2-x1 = 5-4 / 2-1 = 1/1 = 1 > y-y1 = a.(x-x1)........(1,4) => y1=4....x1=1....a=1 y-4 = 1.(x-1) y-4 = x-1 y-4-x+1=0 -x+y-3 = 0 ....(*-1) x-y+3 = 0 >>

  in Equação da reta que passa nos pontos P (2,5) e Q (1,4)? Comment by archie-morgan_6095036d3c0c6 May 2021