Problema de trigonometria?

tgA+tgB+tgC=tgA·tgB·tgC

Siendo A, B y C ángulos de un triángulo(suman 180º)

Comments

  • tg(A+B)=-tg(180-(A+B))=-tgC

    tg(A+B) = (tgA+tgB)/(1-tgA.tgB) = -tgC

    <=> tgA + tgB = -tgC (1-tgA.tgB)

    <=> tgA + tgB + tgC = tgA.tgB.tgC

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