algebra word problem?
a man drove part of a 185mi trip at 50mi/h and the rest at 55mi/h. find the distance she traveled at 50mi/h if her total driving time was 3h and 30min.
please explain how you solved
a man drove part of a 185mi trip at 50mi/h and the rest at 55mi/h. find the distance she traveled at 50mi/h if her total driving time was 3h and 30min.
please explain how you solved
Comments
x = hours at 50mph
y = hours at 55mph
x + y = 210/60
50x + 55y = 185
(the 210 came from 3h and 30mins in minute form, but since everything is in hours, you have to divide it by 60)
Then solve.
Answer:
x = 1.5 hours
y = 2 hours
Two hours at 55mph = 110 miles
One hour at 50mph = 50 miles
Which equals 160 miles.
Half an hour at 50mph = 25 miles.
160 + 25 = 185 miles.
(therefore two hours at 55, and one and a half at 50)
50 h1 + 55 h2 =185, h1 + h2 == 3 + 30/60
h1 = 3/2,
h2= 2
50 x h1 = 75 mi
3.5*50 = 175
you need ten more miles or two more hours driving 5 miles an hour faster. There is an equation to figure this out but I just woke up
Luckily maellstorm is awake