how do i solve this algebra problem?

x(squared)-x-6=0

step by step

i just dont get it...

Comments

  • (x-3)(x+2)

    x=3

    x=-2

  • is that a factoring?

    x(squared)-x-6=0

    .if its is factoring then the answer is:

    (x-3)(x+2)

    x (squared) is the quadratic term, then -x serve as the middle term then , -6 is ur constant..

    .that is the formula of == ax(squared) + by + c=0

    .. their are 5 types of factoring , and ur given problem is what we called the difference of 2 terms.

    . now to get the factor of the diff. of 2 terms you have to know what are the factors of your constant (that is ur -6), that the product of your constant is your middle term.(that is -x and the constant on this is -1 ryt?) , so the only factor of 6 which is the product of -1 is -3+2 = -1., so u use -3 and 2,,then after that, factor the quadratic term, w/c is ur x(squared) that is = x mutiply by x.. ryt?

    .then you may get it.

    .that is

    (x-3)(x+2)

    .. i hope u could get it, im sorry im not that good to explain in english language,, .. =]

    .but i hope it helps..=]

  • well x(squared)-x-6=0

    you do the "magic x" to find the two binomials, which when factored should equal your original problem:

    (x-3)(x+2)=0

    set both equations equal to zero:

    x-3=0 x+2=0

    x=3 x=-2

    those are the answers :] hope this helped!

  • (x*x)-x-6=0

    (3*3)-3-6=0

    9-3-6=0

    6-6=0

    x=3 because 3 times 3 is 9, 9 minus 3 is 6 and 6 minus 6 is 0.

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