how do i solve this algebra problem?

mon

x(squared)-x-6=0

step by step

i just dont get it...

anonymous

(x-3)(x+2)

x=3

x=-2

finley-lloyd_60be62a7bef25

is that a factoring?

x(squared)-x-6=0

.if its is factoring then the answer is:

(x-3)(x+2)

x (squared) is the quadratic term, then -x serve as the middle term then , -6 is ur constant..

.that is the formula of == ax(squared) + by + c=0

.. their are 5 types of factoring , and ur given problem is what we called the difference of 2 terms.

. now to get the factor of the diff. of 2 terms you have to know what are the factors of your constant (that is ur -6), that the product of your constant is your middle term.(that is -x and the constant on this is -1 ryt?) , so the only factor of 6 which is the product of -1 is -3+2 = -1., so u use -3 and 2,,then after that, factor the quadratic term, w/c is ur x(squared) that is = x mutiply by x.. ryt?

.then you may get it.

.that is

(x-3)(x+2)

.. i hope u could get it, im sorry im not that good to explain in english language,, .. =]

.but i hope it helps..=]

jollyhappy

well x(squared)-x-6=0

you do the "magic x" to find the two binomials, which when factored should equal your original problem:

(x-3)(x+2)=0

set both equations equal to zero:

x-3=0 x+2=0

x=3 x=-2

those are the answers :] hope this helped!

love-is-gender-blind

(x*x)-x-6=0

(3*3)-3-6=0

9-3-6=0

6-6=0

x=3 because 3 times 3 is 9, 9 minus 3 is 6 and 6 minus 6 is 0.