help! for algebra problem?

Comments

• yarhg-v

  June 2021

  it cant work the other way around and become 2 it would become -60

  12x-31=2x+29 so you add 31 to both sides of the equation and get 12x=2x+60 then you subtract 2x from both sides so it's 10x=60 then you just divide by 10 and get x=6

  you could do it the other way and subtract 29 from both sides and get 12x-60=2x Then you can subtract 12x from both sides and get -60=-10x so then you just divide both sides by -10 and receive 6=x

  I prefer the first choice since you dont have to divide with negatives

  On your second problem subtract 2 from both sides so you end up with a/11=2

  Now to solve for (a) you need to isolate it so multiply both sides by 11 so you should get a=22
• mae

  June 2021

  Here's how I would answer it:

  12x-31=2x+29

  Step 1:subtract 2x from both sides

  10x-31=29

  Step 2:add 31 to both sides

  10x=60

  Step 3:divide 10 from both sides

  X=6

  And for the other one:

  a/11+2=4

  Multiply 11 by both sides and it becomes a+2=44

  Then subtract 2 from both sides

  A=42
• willy-tell

  June 2021

  Try thinking of it differently. Do the same thing to both sides of the equation.

  12x-31=2x+29

  Add 31 to both sides to get 12x-31+31=2x+29+31 = 12x=2x+60 then subtract 2x from both sides and get 12x-2x=2x-2x+60 = 10x=60

  10x=60 so divide both sides by 10 :

  x=6
• raj

  June 2021

  Hey, the first part has been answered correctly..

  The second part is answered incorrectly by 'Mae'.

  If you multiply both sides by 11, you get:

  a+22=44 (and not as mentioned); a=22

  (or)

  first, subtract 2 from both sides, you get:

  a/11=2; multiply 11 on both sides; a=22

  Cheers!
• anonymous

  June 2021

  yeah, thats right. add 31 to both sides. the subtract 2x on both sides, then divide 10 on both sides and get ( X=6 ) as you final answer!
• jessica-turner_60bcaabe203b5

  June 2021

  ya that right smart
• harvey-davies_60bcaabf3b26d

  June 2021

  yep.