help! for algebra problem?

friends

in my question here

12x-31=2x+29

is 31 supposed to swap over to 29 so it will be 60 or the other way around so its 2

Update:

how do i do this also?

a/11+2=4

yarhg-v

it cant work the other way around and become 2 it would become -60

12x-31=2x+29 so you add 31 to both sides of the equation and get 12x=2x+60 then you subtract 2x from both sides so it's 10x=60 then you just divide by 10 and get x=6

you could do it the other way and subtract 29 from both sides and get 12x-60=2x Then you can subtract 12x from both sides and get -60=-10x so then you just divide both sides by -10 and receive 6=x

I prefer the first choice since you dont have to divide with negatives

On your second problem subtract 2 from both sides so you end up with a/11=2

Now to solve for (a) you need to isolate it so multiply both sides by 11 so you should get a=22

mae

Here's how I would answer it:

12x-31=2x+29

Step 1:subtract 2x from both sides

10x-31=29

Step 2:add 31 to both sides

10x=60

Step 3:divide 10 from both sides

X=6

And for the other one:

a/11+2=4

Multiply 11 by both sides and it becomes a+2=44

Then subtract 2 from both sides

A=42

willy-tell

Try thinking of it differently. Do the same thing to both sides of the equation.

12x-31=2x+29

Add 31 to both sides to get 12x-31+31=2x+29+31 = 12x=2x+60 then subtract 2x from both sides and get 12x-2x=2x-2x+60 = 10x=60

10x=60 so divide both sides by 10 :

x=6

raj

Hey, the first part has been answered correctly..

The second part is answered incorrectly by 'Mae'.

If you multiply both sides by 11, you get:

a+22=44 (and not as mentioned); a=22

(or)

first, subtract 2 from both sides, you get:

a/11=2; multiply 11 on both sides; a=22

Cheers!

anonymous

yeah, thats right. add 31 to both sides. the subtract 2x on both sides, then divide 10 on both sides and get ( X=6 ) as you final answer!

jessica-turner_60bcaabe203b5

ya that right smart

harvey-davies_60bcaabf3b26d

yep.