How do i solve this algebra problem?

Comments

  • 0<2+3x<8

    step 1:subtract 2 from both sides

    (it'll be) 0-2 <3x< 8-2 = -2< 3x < 6

    now divide everything by 3 (make sure you switch both signs too)

    (now it'll be) -2/3 > x > 6/3 = -2/3 > x > 2

    your answer is negative two thirds is greater than x which is greater than 2 :]

  • 0<3x<8-2

    0<3x<6

    0<x<2

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