Algebra math problem Help?

Comments

• some1

  May 2021

  just take a common denominator which would be (x+9)*x. Then, solve.

  = [(x*x) + {(x-9)*(x+9)}] / ((x+9)*x) = 0 =>[(x^2) + (x^2) - 81] / [(x^2) +9x] = 0

  => [2*(x^2) -81] / [(x^2) +9x] = 0 NOW, multiply both sides by [(x^2) +9x]

  => 2(x^2) - 81 = 0

  when you solve this you will get,

  x = +9/ square root(2) and -9/ square root(2)
• devinity04230

  May 2021

  the Least Common Multiple is (x+9) and x

  x/(x+9) + (x-9)/x

  for the left side of the equation, you are going to multiple the top and bottom by x

  for the right side of the equation, you are going to multiple the top and bottom by x+9

  this will give us a common denominator of x(x+9)

  the top becomes:

  x(x) + (x-9)(x+9)

  remember the denominator is x(x+9)

  x(x) + (x-9)(x+9) over x(x+9)

  compute the numerator

  x^2 + x^2 - 81 over x(x+9)

  now we can add the x^2 together and get the answer:

  2x^2 - 81 over x(x+9)

  2x^2 - 81/ x(x+9)

  Hope this helps!!