Algebra math problem Help?

Comments

  • just take a common denominator which would be (x+9)*x. Then, solve.

    = [(x*x) + {(x-9)*(x+9)}] / ((x+9)*x) = 0 =>[(x^2) + (x^2) - 81] / [(x^2) +9x] = 0

    => [2*(x^2) -81] / [(x^2) +9x] = 0 NOW, multiply both sides by [(x^2) +9x]

    => 2(x^2) - 81 = 0

    when you solve this you will get,

    x = +9/ square root(2) and -9/ square root(2)

  • the Least Common Multiple is (x+9) and x

    x/(x+9) + (x-9)/x

    for the left side of the equation, you are going to multiple the top and bottom by x

    for the right side of the equation, you are going to multiple the top and bottom by x+9

    this will give us a common denominator of x(x+9)

    the top becomes:

    x(x) + (x-9)(x+9)

    remember the denominator is x(x+9)

    x(x) + (x-9)(x+9) over x(x+9)

    compute the numerator

    x^2 + x^2 - 81 over x(x+9)

    now we can add the x^2 together and get the answer:

    2x^2 - 81 over x(x+9)

    2x^2 - 81/ x(x+9)

    Hope this helps!!

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