RL Series Circuit... Help please!!?

Consider a series RL circuit with R= 63.0 Ω and an unknown inductor L, driven by an AC emf with Erms= 38.0 Volts at frequency f= 6.90 kHz. If we measure the current in the circuit, we find Irms= 0.185 Amps.

a. What is the inductance L?

b. What is the magnitude of the phase angle between the applied voltage and the current?

c. What is the ratio of the power dissipated in the resistor to the power that would be dissipated if the inductor were not in the circuit? (Assume that Erms stays the same.)

I already answered B.... Please help me to answer A and C with procedure because I havent been able to do it. Thank you!!!!

Comments

  • Capacitive Reactance Xc = 1/(2πfC)

    Inductive Reactance Xʟ = 2πfL

    Impedance Z = √(R² + X²)

    where X = Xʟ – Xc

    Phase angle θ = arctan (X/R)

    Xc, Xʟ, Z are in Ω, f is in Hz

    C in farads, L in Henrys

    Given those numbers, the impedance is 38/0.185 = 205 ohms

    Z = √(R² + X²) = 205

    R² + X² = 42200

    X² = 42200 – 63²

    X = 196 ohms

    Xʟ = 2πfL = 196

    L = 0.00451 H or 4.51 mH

    θ = arctan (X/R) = arctan (196/63) = 72.2º

    Voltage across R is 0.185 x 43 = 8.0 volts

    power = 8 x 0.185 = 1.47 watts

    R alone, power is 38²/43 = 33.6 watts

    (how could you do b without doing a first?)

    .

  • Series Rl Circuit

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