SAT Free-Response problem...?

Hello. Could someone help me figure out how to get to the answer in this problem?

Let the function h be defined by h(x)=14+(x^2/4). If h(2m)=9m, what is one possible value of m?

The answer can be both 2 or 7, but HOW do I get there?!

Comments

  • Hi Johny,

    We know h(x) = 14 + (x^2)/4. We need to find h(2m). So plug this into the function. Everywhere there is an x in the function, plug in 2m.

    h(x) = 14 + (x^2)/4

    h(2m) = 14 + ((2m)^2)/4

    h(2m) = 14 + ((2^2)(m^2)) /4

    h(2m) = 14 + (4m^2)/4 The 4s cancel out.

    h(2m) = 14 + m^2.

    The question tells us that h(2m) also equals 9m, so set these two values equal:

    h(2m) = 14 + m^2

    h(2m) = 9m

    So 9m = 14 + m^2

    Now it's up to FOIL:

    9m = 14 + m^2

    m^2 - 9m + 14 = 0

    (m - )(m - ) = 0

    (m - 2)(m - 7) = 0

    m =2 and m = 7

    I hope that helps!

  • Derive derive derive drive

  • you should ask your teacher @_@

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