SAT Free-Response problem...?
Hello. Could someone help me figure out how to get to the answer in this problem?
Let the function h be defined by h(x)=14+(x^2/4). If h(2m)=9m, what is one possible value of m?
The answer can be both 2 or 7, but HOW do I get there?!
Comments
Hi Johny,
We know h(x) = 14 + (x^2)/4. We need to find h(2m). So plug this into the function. Everywhere there is an x in the function, plug in 2m.
h(x) = 14 + (x^2)/4
h(2m) = 14 + ((2m)^2)/4
h(2m) = 14 + ((2^2)(m^2)) /4
h(2m) = 14 + (4m^2)/4 The 4s cancel out.
h(2m) = 14 + m^2.
The question tells us that h(2m) also equals 9m, so set these two values equal:
h(2m) = 14 + m^2
h(2m) = 9m
So 9m = 14 + m^2
Now it's up to FOIL:
9m = 14 + m^2
m^2 - 9m + 14 = 0
(m - )(m - ) = 0
(m - 2)(m - 7) = 0
m =2 and m = 7
I hope that helps!
Derive derive derive drive
you should ask your teacher @_@