How do you check this Algebra problem?
2[ 4-2 ( 3-x )] - 1 = 4[ 2 ( 4x-3 ) +7 ] - 25
2(4 - 6 + 2x) - 1= 4(8x - 6 + 7) - 25
8 - 12 + 4x - 1= 32x - 24 + 28 - 25
-5 + 4x= 32x - 21
16= 28x
4/7= x
2[ 4-2 ( 3-x )] - 1 = 4[ 2 ( 4x-3 ) +7 ] - 25
2(4 - 6 + 2x) - 1= 4(8x - 6 + 7) - 25
8 - 12 + 4x - 1= 32x - 24 + 28 - 25
-5 + 4x= 32x - 21
16= 28x
4/7= x
Comments
you substitute the value of x in the equation, so every time you see an x in the first equation, 2[ 4-2 ( 3-x )] - 1 = 4[ 2 ( 4x-3 ) +7 ] - 25, you would put 4/7 in. The equation should be 2[ 4-2 ( 3-4/7)] - 1 = 4[ 2 ( 4(4/7)-3 ) +7 ] - 25 . Hope I helped!
substitute 4/7 for x and check to see if it still works. if it does then its right
Put your answer in for x. if it equals out, then you are right.