How do I solve his algebra problem?

The problem is:

5-3(2x-2)=22

You have to solve for X.

Comments

  • I think some of the previous answers are questionable. The answer is positive.

    If your unsure and you have a graphing calculator, put the left side of the equation in Y1 and the right side in Y2. Find the intersection and that is x.

    Otherwise, order of operations...Please Excuse My Dear Aunt Sally (parenthesis, exponents, multiplication, division, addition, subtraction)

    5-3(2x-2)=22---------->simplify what's outside the parenthesis since you can no longer simplify what's in the parenthesis.

    2(2x-2)=22-----------> Distribute the 2 by multiplying it by everything in the parenthesis.

    2(2x) + 2(-2)=22-------->simplfy

    4x-4=22--------------> bring like terms on the same side; add 4 to both sides

    4x-4(+4)=22+4--------->simplfy

    4x=26-------------> divide both sides by 4

    4x/4=26/4

    x=6.5

    If unsure plug your answer back in the primary equation.

    5-3(2(6.5)-2)=22

    5-3(13-2)=22

    2(11)=22

    22=22

  • 5-3(2x-2) = 22 -----> multiply through the parenthesis

    5 - 6x +6 = 22 ----->

    -6x + 11 = 22 -----> subtract 11 from each side

    -6x = 11 ----->

    x = -11/6 = -1 5/6

    *BTW, Tyler up there is wrong. When multiplying through the parenthesis he forgot he was subtracting a negative number, therefor it becomes adding the six, not subtracting it.

  • 5-3(2x-2)=22

    -3•2x=-6x

    -3•-2=6

    5-6x-6=22

    -5 -5

    -6x-6=17

    +6 +6

    -6x=23

    Divide by -6 from both sides and you get x=3.8 At least that's how I got it. You may have learned it a different way. :P Hope this helped! :D

  • look in your book or ask your teacher tomorrow - so that they know what to spend more classroom time on.

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