how do you factor (x-3)^2-3(x-3)-28?

krizzy

im having a hard time with this one

harish

(x - 3)^2 - 3(x - 3) - 28

= (x - 3)^2 - 7(x - 3) + 4(x - 3) - 28

= (x - 3)(x - 3 - 7) + 4(x - 3 - 7)

= (x - 3 - 7)(x - 3 + 4)

= (x - 10)(x + 1)

anonymous

Expand

(x-3)^2

=x^2-6x+9-3x+9-28

=x^2-9x-10

=(x+1)(x-10)

mike-g

z = (x-3)

z^2-3z-28 = 0

(z-7)(z+4) = 0

(x-10)(x+1)