Algebra problem.?

anonymous

I need to write and solve this equation.

The handicap H of a bowler whose average is A is often found by using the formula H=0.8 (200-A). A bowler's final score for a game is the actual score plus the bowler's handicap. FInd the handicap for a fowler whose average score is 135.

sarah

H = 0.8 (200 - 135)

H = 0.8 (65)

H = 52

hamaki

Your formula is really close if the league's by-laws state that the league handicap will be 80% of the difference between your average and 200. Let handicap = X, single game average = Y which is 135.

So .. X = 80% (200 - Y)

X = 0.8 (200-135)

X = 0.8 (65)

X (Handicap) = 52 pins per game

If the answer had had a decimal point like 52.3, it would have been dropped in league play

general-lee-speaking

First, ignore "A bowler's final score for a game is the actual score plus....." That sentence was put in there to confuse you and is not necessary to solve the problem.

You know the average (A) is 135, so all you do is plug 135 in for "A" in the equation and solve. Use order of operations (PEMDAS) to solve. Solve inside the parentheses (Pemdas) first by subtracting 135 from 200, and you will get 65. Next, multiply (peMdas) 65 by 0.8 to get 52.0, your final answer.

H=0.8(200-A)

H=0.8(200-(135))

H=0.8(65)

H=52.0 (the zero is not necessary)

charlie

A= 135

H=0.8(200-A)

H=0.8(200-135)

H=0.8(65)

H=52

The Handicap for the bowler is 52

432221

H= .8 (200-135) = 52

Calculate, is this right? You're just subbing in A, the average, as 135.

atcha-batcha

the answer is 52

johnathon-c

lol idk srry