DUVIDAS NESSAS QUESTOES?

Alguem me explica como fazer esses exercicios?

(Raiz de 7)^3

(Raiz quadratica de 9)^2

9x^2 -3x =-5/36

Comments

  • 9x² - 3x = - 5/36

    9.[x² - (3/9).x] = - 5/36

    x² - (3/9).x = - 5/324

    x² - (1/3).x = - 5/324

    x² - (1/3).x + (1/6)² = - (5/324) + (1/6)²

    x² - (1/3).x + (1/6)² = - (5/324) + (1/36)

    x² - (1/3).x + (1/6)² = - (5/324) + (9/324)

    x² - (1/3).x + (1/6)² = 4/324

    x² - (1/3).x + (1/6)² = 1/81

    [x - (1/6)]² = [± (1/9)]²

    x - (1/6) = ± (1/9)

    x = (1/6) ± (1/9)

    x = (3/18) ± (2/18)

    x = (3 ± 2)/18

    x₁ = (3 + 2)/18 → x₁ = 5/18

    x₂ = (3 - 2)/18 → x₂ = 1/18

  • ........|¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨ \

    ........|..........2 Pontos ...... |||"|""\__

    ........|__________________|||_|___|)

    ........!(@)';(@)";"""**!(@)(@)****!(@)

Sign In or Register to comment.