How do I do this Physics problem?
A golf ball of mass 4.50 10-2 kg is struck by a club. Contact lasts 2.23 10-4 s, and the ball leaves the tee with a horizontal velocity of 49.0 m/s. Compute the average force the club exerts on the ball by finding its average acceleration.
Magnitude:_____
Comments
Golf ball of mass 4.50x10˙² kg and contact time 2.23x10^-4 s.
Golf ball initial velocity 49.0 m/s
Average Acceleration:
a = (vf - vi) / Δt = 49.0 m/s / 2.23x10^-4 s = 220 m/s² <<< Answer
Average Force:
F = m*a = 4.50x10˙² kg * 220 m/s² = 9888N ≈ 9900 N <<< Answer
Alternative way to calculate/verify by Impulse:
Impulse = Change of Momentum
Impulse = F*Δt where Δt = 2.23x10^-4 sec
Impulse = F*Δt = m*Δv = m*(vf - vi) where vi = 0 and vf = 49.0m/s
F*Δt = m*vf
F = m*vf / Δt = 4.50x10˙² * 49.0 / 2.23x10^-4 = 9888 N
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