Another natural log problem...?

The problem is to simplify e^(1+lnx), i could just do it on my calculator but it would really help to know the steps involved in getting the answer, so if you could type it out, that would be great.

Comments

  • e^(1+lnx) = (e^1)(e^lnx) = ex

  • putting 19 on the different area is a mind-blowing start up--in my opinion, i might pass the stuff interior the organic log, so the two aspects is effective. 19 = ln(2-x) organic log is in straightforward terms a logarithm with a base of e--in case you're taking the two aspects and make it a capability of the backside of the logarithm, you are able to cancel out the logarithm. enable's say we've been coping with a logarithm of the backside of 10, as an occasion.. 3 = log(5+x) 10^3 = 10^log(5+x) 10^3 = 5 + x one thousand = 5 + x x = 995 So do the comparable factor, different than somewhat of turning out to be the two aspects of the equation 10 to the capability of despite you had, make it e to the capability of despite you have. tell me in case you like greater help.

  • Assuming x is knwon,

    Find ln(x)

    Add 1 + ln(x) = y

    Find e^y, done!

    Also, you can do e^(1 + ln(x)), directly!

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