A 120.0-V motor draws a current of 8.40 A when running at normal speed. the back EMF generated by the motor is 114V. what is the resistance of the armature wire?
The effective voltage = 120.0 - 114 = 6V
R = V/I = 6/8.40 = 0.714Ω
Comments
The effective voltage = 120.0 - 114 = 6V
R = V/I = 6/8.40 = 0.714Ω