Algebra Help Requested? :3?
Now, I'm not asking you to solve this. No way. Just simply, if you will, tell me what the name of the process is that I use?
Nadia is at home and Peter is at school which is 6 miles away from home. They start traveling towards each
other at the same time. Nadia is walking at 3.5 miles per hour and Peter is skateboarding at 6 miles per hour.
When will they meet and how far from home is their meeting place?
Comments
D = r t , r = sum of the 2 rates , D is given , find t and then 3.5 t
Step 1: Get a piece of paper
Step 2: Draw a little house on one end and a little school on the other, and a line between them.
Step 3: Choose one of them as the starting point and consider that point zero.
Step 4: Let the length, or distance of the line, d, be 6 miles at the opposite end from the starting point.
Step 5: Ask yourself, what thing do Peter and Nadia have in common here? Answer: They will both be traveling for the same amount of time, t, before they meet.
Step 6: Realize that velocity = distance/time
Step 7: Rearrange this for time: time = distance/velocity.
Step 8: Look at your line and realize that if one person travel some distance x, the other person only has the remaining distance to travel. In other words. If Nadia travels x miles, then Peter travels d-x = 6-x miles.
The equation for Nadia: t = x/3.5
The equation for Peter: t = (6-x)/6
Step 9: Set them equal and solve for x.
Step 10: Take that x and plug it into either the equation for Nadio or the equation for Peter and solve for t. Double check by then plugging x into the equation for the other person to make sure you get the same answer for t.
You're done.