x/(x² - 5x + 6) + ( x² - 9)/ [(x -3)²] = 1
x/(x² - 5x + 6) + (x² - 9)/(x - 3)² = 1
x² - 5x + 6 = (x - 3)*(x - 2)
x² - 9 = (x + 3)*(x - 3)
x/(x - 3)*(x - 2) + (x + 3)*(x - 3)/(x - 3)² = 1
x/(x - 3)*(x - 2) + (x + 3)/(x - 3) = 1
x/(x - 3)*(x - 2) + (x + 3)*(x - 2)/(x - 3)*(x - 2) = 1
x + (x + 3)*(x - 2) = (x - 3)*(x - 2)
x + x² + x - 6 = x² - 5x + 6
7x = 12
x = 12/7
pronto
Sei se está certo não, mas x= 12/7
Comments
x/(x² - 5x + 6) + (x² - 9)/(x - 3)² = 1
x² - 5x + 6 = (x - 3)*(x - 2)
x² - 9 = (x + 3)*(x - 3)
x/(x - 3)*(x - 2) + (x + 3)*(x - 3)/(x - 3)² = 1
x/(x - 3)*(x - 2) + (x + 3)/(x - 3) = 1
x/(x - 3)*(x - 2) + (x + 3)*(x - 2)/(x - 3)*(x - 2) = 1
x + (x + 3)*(x - 2) = (x - 3)*(x - 2)
x + x² + x - 6 = x² - 5x + 6
7x = 12
x = 12/7
pronto
Sei se está certo não, mas x= 12/7