Just show how they got 1....(annoying)
Thanks Much!!!!
(sinx/cscx)+(cosx/secx)= sinx·sinx+ cosx·cosx = sin²3x+cos²x=1
Saludos.
(sinx/cscx)+(cosx/secx) = 1
(sinx/(1/sinx)) + (cosx/(1/cosx) = 1....... [ NOTE: secx = 1/cosx and cscx = 1/sinx]
(sin^2 x) + (cos^2 x) =1.........[NOTE: this is an identity]
1 =1
cosx/(secx)(sinx) = cosx/(sinx/cosx) = cos^(2)x / sinx you should be able to take it from there....
Comments
(sinx/cscx)+(cosx/secx)= sinx·sinx+ cosx·cosx = sin²3x+cos²x=1
Saludos.
(sinx/cscx)+(cosx/secx) = 1
(sinx/(1/sinx)) + (cosx/(1/cosx) = 1....... [ NOTE: secx = 1/cosx and cscx = 1/sinx]
(sin^2 x) + (cos^2 x) =1.........[NOTE: this is an identity]
1 =1
cosx/(secx)(sinx) = cosx/(sinx/cosx) = cos^(2)x / sinx you should be able to take it from there....