How do you solve this algebra problem?

anonymous

4x + 8 - 2x - 1 < 3(x+2) -x

______________________

....4.........3....

(To clarify, it's 4x+8 divided by 4 minus 2x-1 divided by 3 is less than 3(x+2) minus x.)

mel

First of all, make it the same denominator at the left side:

multiply(4x + 8)/4 by 3 and (2x -1)/3 by 4.

Then simplify it

you should get (x+7)/3 < 2x+6

make it (x+7)/3 < 2x+6/1 and cross multiply

Which give you x+7 < 6x+18

Bring x to one side, number to the other

Final answer is negative fraction.

Correct me if I'm wrong.

tom4bucs

4x + 8/4 reduces to

x + 2

2x - 1 over 3 will not reduce (so we multiply by three)

3(x + 2) - x = 2x + 6

so that

x + 2 -{2x-1/3} < 2x + 6

3x + 6 -2x + 1 < 6x + 18

5x + 7 < 6x +18

0 < X + 11

-11 < X

I guess - sorry I am so sleepy

david

(4x+8)/4 - (2x-1)/3 < 3(x+2)-1 simplyfing we get:

x+2 -(2x-1)/3 < 3x +5 now multiply both sides by 3:

= 3x + 6 -2x +1 < 9x +15

= x + 7 < 9x + 15 now subtract x from both sides

= 7 < 8x +15 now subtract 15 from both sides

= -8 < 8x or -1 <x

x>-1

kris

(4x + 8 )/4 - (2x-1)/3 < 3(x+2)-x

(4x + 8)/4 = x + 2

x+2 - (2x-1)/3 < 3(x+2)-x || ( )*3

3x + 6 - (2x-1) < 9(x+2)-3x

3x -2x + 6+1 < 9x+18 -3x

3x-2x-9x+3x <18-6-1

-5x <11

x> - 2,2

luke-anderson_60b9350f4c6b2

x+2-(2/3)x-(1/3)<3x+6-x...............first distribute everything

(1/3)x+(5/3)<2x+6.......................combine like terms

(5/3)<(5/3)x+6............................get all of the x's on one side

-(13/3)<(5/3)x.............................get all of the constants on one side

-(13/5)<x....................................divide both sides by 5/3 to get x by itself

so, x>-13/5 or x>-2.6 is the final answer!!!

screaming-monk

Sorry mate; it is far too convoluted to commit time to deciphering

Re-express and I will help. Hint, use more brackets, parentheses ...