If you take the two equations one at a time there is many (infinity) solutions coz for a value of "x" there is one value also for "y".
But since you take those two equations as a system, there is only one solution coz these are equations of lines and lines can meet only on one point (exception if they are one over the other).
right here thake 2x-y=32 and subtract y making it 2x=32+y Then take y-5x=13 and subtract y making it 5x=13-y the y's cancel then you definately upload the relax issues togeather so ur answer would desire to be7x=40 5 then you definately divide so the respond is x=6.40 two then you definately purely pass on from there wish i helped!;-)
Comments
If you take the two equations one at a time there is many (infinity) solutions coz for a value of "x" there is one value also for "y".
But since you take those two equations as a system, there is only one solution coz these are equations of lines and lines can meet only on one point (exception if they are one over the other).
- x - 3y = 6
-3y = x + 6
y = -(x+6)/3
Replace in the second equation :
3x + y = -4
3x - (x + 6)/3 = -4
Smallest common denominator is 3 :
9x - x - 6 = -12
8x = -12 + 6
x = -6 / 8
x = -3/4
And for y :
3*(-3/4) + y = -4
-9/4 + y = -4
y = -4 + 9/4
y = -7/4
Proof :
-x - 3y = 6
3/4 + 21/4 = 6
24/4 = 6 :ok
3x + y = -4
-9/4 - 7/4 = -4
-16/4 = -4 :ok
So the answer is B
where x = -3/4 and y = -7/4
right here thake 2x-y=32 and subtract y making it 2x=32+y Then take y-5x=13 and subtract y making it 5x=13-y the y's cancel then you definately upload the relax issues togeather so ur answer would desire to be7x=40 5 then you definately divide so the respond is x=6.40 two then you definately purely pass on from there wish i helped!;-)