How do you graph this problem?
My teacher likes to give us work and teach us the next day. I wouldn't have a problem with that, but we don't have math books. Can anyone explain how to graph this please? x^2 + 2x - 8 = 0 The rules that accompany the problem are "Solve each quadratic equation by graphing the related quadratic function and finding the X-intercepts. If there are no real solutions, right no real solutions." Please, and thank you! 
Comments
right no real solutions should be write no real solutions?
X^2+2*X-8
Standard form: a(X-h)²+k = ( X² +2X +1) -1 -8 = (X +1)² -9
X = -1 ±√( 9) = -4, or 2
Axis of symmetry: X= -1; Vertex (minimum)=(h,k)=( -1, -9); y-intercept is (0,-8)
p=1/4a; Focus: (h,k+p)=( -1, -35/4); Directrix: y=k-p=-9.25
Latus: ( -3/2, -35/4) to ( -1/2, -35/4)
Quadratic formula: X = (-b ±√(b²-4ac))/(2a) = ( -2±√( 4 +32))/( 2)
positive discriminant = 36; two real roots: X=-4 and 2
factors: ( X -2)( X +4)
values: (-4, 0) (-2.5, -6.7) (-1, -9) (0, -8) (0.5, -6.7) (2, 0)