How to solve algebra problem?

vic

3y+2 / 5 - y-3 / 10 = -4

bullwinkle

[(3y + 2)/5] - (y - 3)/10 = - 4

clear denominators...multiply by 10...

2(3y + 2) - (y - 3) = - 40

6y + 4 - y + 3 = - 40

5y = - 47

y = (- 47)/5

check

Σ

peter-kelly_60989f38c2165

Find a number that all the denominators go into (5 and 10 both go into 10), so multiply everything by 10:

10(3y + 2) / 5 - 10(y - 3) / 10 = 10(-4)

Simplify the fractions:

2(3y + 2) - 1(y - 3) = 10(-4)

Expand the brackets:

6y + 4 - y + 3 = -40

Combine the like terms:

5y + 7 = -40

Subtract 7 from both sides:

5y = -47

Divide both sides by 5:

y = -47/5

como

Brackets should really be used.

(3y + 2) / 5 - (y - 3) / 10 = - 4

6y + 4 - y + 3 = - 40

5y = - 47

y = - 47/5