Could someone show me how to go about solving this?
Thanks in advance
Derivative of y=cos(e^(-3x))?
y' = -sin(e^(-3x))*(e^(-3x))*(-3)
y' = +3(e^-3x)*sin(e^(-3x)) >==============< ANSWER
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Derivative of y=cos(e^(-3x))?
y' = -sin(e^(-3x))*(e^(-3x))*(-3)
y' = +3(e^-3x)*sin(e^(-3x)) >==============< ANSWER