r(x) = 3x - 1
s(x) = -x -1
find (r o s)(-3) and (s o r)(-3)
I don't know if "Brenda" missed the sequence or not...
(r o s)(-3) =>
s(-3) = -(-3) - 1 = 3 -1 = 2
r(2) = 3 * 2 - 1 = 5
(s o r)(-3) =>
r(-3) = 3 (-3) - 1 = -10
s(-10) = -(-10) - 1 = 9
r(s(-3)) = -(-10) - 1
r(s(-3)) = 10 - 1
r(s(-3)) = 9
s(r(-3)) = -(-10) - 1
s(r(-3)) = 10 - 1
s(r(-3)) = 9
Comments
I don't know if "Brenda" missed the sequence or not...
(r o s)(-3) =>
s(-3) = -(-3) - 1 = 3 -1 = 2
r(2) = 3 * 2 - 1 = 5
(s o r)(-3) =>
r(-3) = 3 (-3) - 1 = -10
s(-10) = -(-10) - 1 = 9
r(s(-3)) = -(-10) - 1
r(s(-3)) = 10 - 1
r(s(-3)) = 9
s(r(-3)) = -(-10) - 1
s(r(-3)) = 10 - 1
s(r(-3)) = 9