Pre-Algebra math problems?
Without graphing tell whether the lines y=2/3x+1 and y=-3/2x+1 are parallel,perpendicular, or neither ?
Then identify the slope and y-intercept of the line with the given equation?
Y=-5x
Y=2x+1
4x-2y=8
For the line with the given equation find the slope of the parallel line and the slope of the
perpendicular line?
Y=6x-3
Y=3/4x+4
Any help ?? And please explain!
Comments
m1=2/3 and m2= -3/2
m1 x m2 = -1. Hence the the two st. lines are perpendicular.
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y = mx +c.
Here y = 5x + 0.
slope = m = 5.
y intercept =0.
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y=2x+1
slope=2 and y intercept = 1.
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4x - 2y = 8.
2y = 4x - 8.
y = 2x - 4.
Therefore slope = 2 and y intercept = - 4.
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y=6x - 3.
slope of the line = 6. Hence, any st. line parallel to this line will be having slope = 6.
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y=3/4 x+4.
slope of this st. line =3/4.
Hence slope of any st. line parallel to this line will be having a slope =3/4.
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Without graphing tell whether the lines y=2/3x+1 and y=-3/2x+1 are parallel,perpendicular, or neither ?
perpendicular since product of y'=-1
Then identify the slope and y-intercept of the line with the given equation?
Y=-5x
slope=-5
y-int= (0,0)
Y=2x+1
slope=2
y-int y=0+1=1
(0,1)
4x-2y=8
2x-y=8
y=2x-8
slope=2
y-int=(0,-8)
For the line with the given equation find the slope of the parallel line and the slope of the
perpendicular line?
Y=6x-3
slope of parallel = m=6
slope of perpendicular =-1/m=-1/6
Y=3/4x+4
sloppe of parallel m=3/4
slope of perp = (3/4)m=-1 , m=-4/3
ok. nicely in accordance to the orders of operation- you ought to do exponents first. So 3 to the 2d power is 9 and three to the third power is 27. you've now 9+2 x 27. next, you ought to do multiplication. So 2 x 27 is fifty 4. you're literally left with 9+fifty 4 that is sixty 3!
Well the first one is perpendicular