algebra problem [ 6(x+3)^-1 - 2(x-1) / x(x-1)^-1 - 3(x+2)^-1 ]?

anonymous

[ 6(x+3)^-1 - 2(x-1) / x(x-1)^-1 - 3(x+2)^-1 ]

anonymous

[ 6/x+3 -2/x-1 ] / [ x/x-1 -3/x+3 ]

[6x-6-2x-6] / (x+3)(x-1) / [x^2+3x-3x+3] / (x-1)(x+3)

[4x-12]/[x^2+3]

fazaldin-a

[ 6(x+3)^-1 - 2(x-1) / x(x-1)^-1 - 3(x+2)^-1 ] =

= 6/(x+3) -2(x-1)(x-1)/x -3/(x+2) = 6/(x+3) -2(x-1)^2/x -3/(x+2) =

= 6/(x+3) -2(x-1)^2/x -3/(x+2) >=================< ANSWER

anonymous

a million. -2x^4 - 6x^2 + 3x + a million divided via x + a million ...2x^3-2x^2-4x+7 and something=-6 2. x^5 + 2x^4 - 3x + 3 divided via x - a million ...x^4+6x^3-6x^2-9 and something=-6 3)attempt: x^3-(3/2)x^2+x+a million