logaritmo quem pode me ajudar?

a) log de base 3 (3.81)

b)log de base 7 (49.343/7)

Comments

  • a) Na base 3:

    log (3.81) =

    log (3) + log (81) =

    1 + 4 = 5

    b) Na base 7:

    log (49.343/7)=

    log(49) + log(343) - log(7)

    2 + 3 -1= 4

  • a) log de base 3: log (3.81) =log (3) + log (81) = 5

    b) log de base 7: log (49.343/7)=log(49) + log(343) - log(7)= 4

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