√ 2, √ (2√ 2), √ (2√(2√ 2))
cant come up with a formula
I'm working on it.
Here's what I have so far.
The first exponent is 1 / 2.
each subsequent exponent increases by geometric series. t_2 = 2^( 1 / 2 + 1 / 4 )
t_3 = 2^( 1 / 2 + 1 / 4 + 1 / 8 )
I solved it. t_n = 2^[ sigma( from 1 to n ) { (1 / 2 )^n } ]
Comments
I'm working on it.
Here's what I have so far.
The first exponent is 1 / 2.
each subsequent exponent increases by geometric series. t_2 = 2^( 1 / 2 + 1 / 4 )
t_3 = 2^( 1 / 2 + 1 / 4 + 1 / 8 )
I solved it. t_n = 2^[ sigma( from 1 to n ) { (1 / 2 )^n } ]