Two Algebra problems?
Stuck on two problems
First problem is to solve the equation
1. 9x^3-18x-4x+8 = 0
My first step was this: 9x^2(x-2) - 4(x-2) = 0
Not sure what to do next, help would be appreciated
The next problem I have is a word problem, The temperature T in Celsius at which water boils is related to the elevation "h" (in meters above sea level) by the formula
h = 1000(100 - T) + 580(100 - T)^2
for 95 <= T <= 100
The problem is, the elevation of Mt. Everest is appromixately 8840 meters. Estimate the temperature at which water boils at the top of this mountain ( Hint use the quadratic formula with x = 100 - T)
I will repeat all my steps as that would be a lot of typing, I first got the problem down to the quadratic formula step to 580T^2 - 117,000T + 5,899,420 = 0
I plugged that into the quad formula to get x = 111.82 celsius, if someone got a different answer please try to explain your steps. Thank you
Comments
x = 4/3
x = 1/3 (-2-sqrt(10))
x = 1/3 (sqrt(10)-2)
graphed it as a parabola
T=96.864
chente
chente