una recta pasa por los puntos A(1,2) y el punto B ( 4,5) determinar cual es el valor de la pendiente de la recta.
Pendiente
m = (5-2)/(4-1) = 3/3 = 1
Ecuación
y - 2 = x - 1
y = x + 1
**************
How do I find the equation for the straight line with two points A (1 ; 2) and B (4 ; 5) ?
The typical equation of a line is: y = mx + b → where m: slope and where b: y-intercept
To calculate m
m = (yB - yA) / (xB - xA) = (5 - 2) / (4 - 1) = 3/3 = 1
The equation of the line becomes: y = x + b
To calculate b
The line passes through A, so the coordinates of this point must verify the equation of the line.
y = x + b
b = y - x → you substitute x and y by the coordinates of the point A (1 ; 2)
b = 2 - 1 = 1
→ The equation of the line is: y = x + 1
¿Porque nosotros tenemos que hacer eso si te lo dieron a vos?
Comments
Pendiente
m = (5-2)/(4-1) = 3/3 = 1
Ecuación
y - 2 = x - 1
y = x + 1
**************
How do I find the equation for the straight line with two points A (1 ; 2) and B (4 ; 5) ?
The typical equation of a line is: y = mx + b → where m: slope and where b: y-intercept
To calculate m
m = (yB - yA) / (xB - xA) = (5 - 2) / (4 - 1) = 3/3 = 1
The equation of the line becomes: y = x + b
To calculate b
The line passes through A, so the coordinates of this point must verify the equation of the line.
y = x + b
b = y - x → you substitute x and y by the coordinates of the point A (1 ; 2)
b = 2 - 1 = 1
→ The equation of the line is: y = x + 1
¿Porque nosotros tenemos que hacer eso si te lo dieron a vos?