How do you integrate e^(2-x)?

statistics-student

rapidfire

Integration by substitution is not required because it is only a linear function within the beacket. Simply integrate as normal then divide by the derivative of the bracket.

∫ e ^ (2 - x) dx

e ^ (2 - x) / -1 + C

-e ^ (2 - x) + C

anonymous

reframe the question as

int e^(2-x) = - int -e^(2-x)

put

(2-x) as t therefore, -xdx = dt

= - int e^t dt

= - e^t

= - e^(2-x)

nerd

= e^2 * e^-x

Integrating it

= e^2 * (- e^-x)

= -(e^2 * e^-x)

Hope this will help

sophie-cooper_60b1a033304ab

e^(2-x)=e^2(e^(-x))

int(e^2(e^-x))=e^2int(e^(-x))

=e^2*-e^(-x)

=-e^(2-x)