Na2CO3 + 2HCl --> CO2 + H2O + 2NaCl?

weight of Na2CO3=2.028g;mass of CO2=0.810 g

What is the percentage yield from Na2CO3 being added to HCl to form CO2?

List reasons why it may or may not be 100%.

Comments

  • MW Na2CO3 105.9784 g mol−1

    MW CO2 44.01 g mol−1

    Na2CO3 is 2.028g or 0.0192 mol

    CO2 is 0.810 g or 0.0184 mol

    only lacking then 0.0192-0.0184 = 7.5x10^-4 mol

    not reacting 7.5x10^-4 mol*105.9784 g mol−1=0.079g

    yield is around 96%

    not 100% surely because the solid passivates with salt clusters

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