To solve an equation of the form x^2 - Bx + C, you have to be able to factorize it as follows:
(x - M)(x - N)
where M + N = B, and M(N) = C. There is no solution for this. No pair of whole number factors of 2 add up to anything greater than 3. They would have to add up to 9 for there to be a solution.
If you are allowed to use numbers that aren't whole numbers, 8.772 and 0.228 will get you REALLY close. They add up to 9 and when you multiply them, you get 2.000016.
Comments
No. It does not factorize.
To solve an equation of the form x^2 - Bx + C, you have to be able to factorize it as follows:
(x - M)(x - N)
where M + N = B, and M(N) = C. There is no solution for this. No pair of whole number factors of 2 add up to anything greater than 3. They would have to add up to 9 for there to be a solution.
If you are allowed to use numbers that aren't whole numbers, 8.772 and 0.228 will get you REALLY close. They add up to 9 and when you multiply them, you get 2.000016.
No, it doesn't factorize.
Picture the graph of y = x^2 - 9x + 2. It's a parabola that opens upwards.
It crosses the x-axis twice, at which point y = 0.
Use the quadratic formula to solve the equation x^2 - 9x + 2 = 0. That gives you the two intercepts.
x^2 - 9x + 2 < 0 for values of x that are between those intercepts.
Use the quadratic equation
Use the quadratic formula.
yeah